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• # Conversion of Specific fuel Consumptions

Discussion in 'Calculations' started by hemcrop, Aug 8, 2011.

1. ### hemcropNew Member

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May 2011
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Dear All,

I have Data Sheet of a Diesel Engine of capacity 1650KVA/ 1320KW. The fuel Consumption of Engine is given in terms of g/kWh for specific loads as shown below.

Specific Fuel Consumption (be) - 100% FSP - 193 g/kWh
Specific Fuel Consumption (be) - 75% FSP - 194 g/kWh
Specific Fuel Consumption (be) - 50% FSP- 201 g/kWh
Specific Fuel Consumption (be) - 25% FSP- 228 g/kWh

please tell me how to convert above consumptions values from g/kWh to liters.
Is there any formula involved to convert it/

Cheers,

Hemcrop

2.
3. ### mihaiNew Member

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Aug 2011
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Hy!

You can use this formula:
CI=c x P x 1/ro

where: c - specific consumption (g/kWh)
P - power (kW)
ro - fuel density (kg/m3)
Your result CI (fuel consumption in time) will be in m3/h. (x 1000 for liters/h)

Cheers,
Mihai

4. ### hemcropNew Member

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May 2011
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Thanks A lot mihai. This Definitely going to help me a lot.

Cheers
Hemcrop

5. ### mihaiNew Member

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Aug 2011
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P - is power for a specific load (25%, 50%, 75%, 100%), in your case, 100% is 1320kW.

So, your consumption for one hour (if, for example, you are using gasoline ro=835kg/m3):

CI (100%) = 0,193kg/kWh x 1/835kg/m3 x 1320kW = 0,305 m3/h = 305 l/h

cheers,
Mihai

6. ### brijsMember

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Aug 2011
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Hi all,
Thanks mihai, The formula CI=c x P x 1/ro is absolutely correct.

Joined:
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