• Welcome to engineeringclicks.com
  • Crank Torque/Piston Force Question

    Discussion in 'Calculations' started by Idiotic, Jun 29, 2012.

    1. Jonathan J

      Jonathan J Member

      Joined:
      Sep 2012
      Posts:
      5
      Likes Received:
      0
      Sounds like all answers are in agreement, but the easiest way to explain where the equations come from is to Sum Forces and Moments about a point.

      The following is copied from software output:

      Point A is crank, point B is pin joint, point C is piston.

      ∑M = 0 => −17.160 × RB3[Y] − 5.436 × RB3[X] = −M1
      ∑F[X] = 0 => RA3[X] + RB3[X] + R38Fp3[X] = 0
      ∑F[Y] = 0 => RA3[Y] + RB3[Y] + R38Fp3[Y] = 0
      ∑F[X] = 0 => −RA3[X] = 0
      ∑F[Y] = 0 => −RA3[Y] = 0
      ∑F[X] = 0 => −RB3[X] − RB5[X] = 0
      ∑F[Y] = 0 => −RB3[Y] − RB5[Y] = 0

      Resuts
      RA3[X] = 0.000 N
      RA3[Y] = 0.000 N
      RB3[X] = 3939.999 N
      RB3[Y] = 267.077 N
      RB5[X] = −3939.999 N
      RB5[Y] = −267.077 N

      And of course,
      Shear and Bending
      Length CB =3949.04N compression
      Length BA = 1444.44N shear & 26000Nmm

      (Note the slight variation in answer is because I havent much time and have some rounding errors on inputs. But the answer shows that the preceding post values are certainly correct)

      Hope you found that interesting.
       
    2.  

    Share This Page

    1. This site uses cookies. By continuing to use this site, you are agreeing to our use of cookies.
      Dismiss Notice