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• # Horizontal reaction forces

Discussion in 'Calculations' started by NMC, Dec 19, 2018.

1. ### NMCMember

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Dec 2018
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Hi all,

After a bit of help if possible.

How do I go about calculating the horizontal reaction forces for points A and B on the attached pic. Again I am going to assume the principles of static equilibrium ∑ Fx = 0 ...∑ M = 0
I understand that all forces must 'balance' however, do I need to take into consideration all measurements etc? How do I go about that?

Thanks for any help. 2.
3. ### s.weinbergWell-Known MemberEngineeringClicks Expert

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Nov 2012
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Where exactly is that force being applied? Is weight being considered?

4. ### MSHOfficialWell-Known MemberEngineeringClicks Expert

Joined:
Nov 2018
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So once you get the location of exactly applied load, you can put the unknown horizontal reaction forces at A and B (namely Fa and Fb both pointing downwards). Then go ahead and write the two equilibrium equations.

1) Fx=0 that will give Fa+Fb+22kN = 0

2) M=0 take that at the point A.

So itll be something like, Fb(0.4-0.1)-22kN(e)=0

e = distance between force 22kN and point A.

from equation 2 you can find Fb= 22kN(e)/0.3 and this will be in kN.

After finding Fb you can use equation number 1 to find Fa = -Fb-22kN and this will also be in kN.

And there you have the two reactions.