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  • Horizontal reaction forces

    Discussion in 'Calculations' started by NMC, Dec 19, 2018.

    1. NMC

      NMC Member

      Dec 2018
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      Hi all,

      After a bit of help if possible.

      How do I go about calculating the horizontal reaction forces for points A and B on the attached pic. Again I am going to assume the principles of static equilibrium ∑ Fx = 0 ...∑ M = 0
      I understand that all forces must 'balance' however, do I need to take into consideration all measurements etc? How do I go about that?

      Thanks for any help. horizontal reaction.gif
    3. s.weinberg

      s.weinberg Well-Known Member EngineeringClicks Expert

      Nov 2012
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      Where exactly is that force being applied? Is weight being considered?
    4. MSHOfficial

      MSHOfficial Well-Known Member EngineeringClicks Expert

      Nov 2018
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      So once you get the location of exactly applied load, you can put the unknown horizontal reaction forces at A and B (namely Fa and Fb both pointing downwards). Then go ahead and write the two equilibrium equations.

      1) Fx=0 that will give Fa+Fb+22kN = 0

      2) M=0 take that at the point A.

      So itll be something like, Fb(0.4-0.1)-22kN(e)=0

      e = distance between force 22kN and point A.

      from equation 2 you can find Fb= 22kN(e)/0.3 and this will be in kN.

      After finding Fb you can use equation number 1 to find Fa = -Fb-22kN and this will also be in kN.

      And there you have the two reactions.

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